morganison10p38drr morganison10p38drr

19-05-2018
Mathematics

contestada

Simplify
(4y^2-13y+3)/2y^2-5y-12 multiplied by
(2y^2+9y+9)/16y^2-1) Multiplied by
(Y^2+3y-28)/y^2-9)

Respuesta :

19-05-2018

After factoring each polynomial and canceling the resulting binomials that appear in both the numerator and denominator, you are left with this fraction for your answer:

[tex] \frac{y+7}{4y+1} [/tex]

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