mikemike215
mikemike215 mikemike215
  • 20-05-2018
  • Mathematics
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Marietta129
Marietta129 Marietta129
  • 20-05-2018
2. [tex] \frac{4^3-2^2}{ \sqrt{81} - \sqrt{16}} [/tex]
 = [tex] \frac{64-4}{9-4} [/tex]
 = [tex] \frac{60}{5} [/tex]
 = 12
'B. 12' is the answer to question 2.

3. The answer to this question is 'B. No, because -1(-1) = 1'


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