[tex] y=(2x+3)^2 = 4x^2 +12x +9 [/tex]
Taking 4 out from first two terms, we will get
[tex] y=4(x^2+3x)+9 [/tex]
Now we divide the coefficient of x by 2 and add and subtract the square of the result, we will get
[tex] y=4(x^2+3x+\frac{9}{4}-\frac{9}{4})+9 [/tex]
Distributing 4
[tex] y=4(x+\frac{3}{2})^2+9-9 [/tex]
Cancelling 9
[tex] y=4(x+\frac{3}{2})^2 [/tex]
And that's the required standard form.
Answer:
First Part
answer is D ( 0 = 4x2 + 12x + 9 )
Second part
a=4
b=12
c=9
Step-by-step explanation:
EDGE 2021
