The answer is
mass = 489g
The explanation:
1- iron (III) sulfate
chemical formula is
Fe2(SO4)3
2- the molar mass of Fe2(SO4)3 is
= 55.8*2 + 32*3 + (16*4)*3 =399.9 g/mol
3- To get the mass we can use this formula:
Mass = moles * molar mass
= 1.223 mol * 399.9 g/mol
= 489 g
∴ the mass in grams of 1.223 mol iron(iii) sulfate = 489g
