By definition, the generic equation of the line is given by:
[tex] y = mx + b [/tex]
Where,
m: slope of the line
b: cutting point with vertical axis
For this case we have:
[tex] m = \frac{5}{6} [/tex]
[tex] b = 12 [/tex]
Thus, substituting in the generic equation of the line we have:
[tex] y = \frac{5}{6} x + 12 [/tex]
Answer:
The equation of the line is given by:
[tex] y = \frac{5}{6} x + 12 [/tex]
