For this case we have that the distance between two points is given by:
[tex]d = \sqrt{(y2-y1)^2+(x2-x1)^2}[/tex]
Given the points:
[tex](x1, y1) = (1, -4)(x2, y2) = (1,0)[/tex]
We substitute in the formula:
[tex]d = \sqrt{(0 - (- 4)) ^ 2 + (1-1) ^ 2}[/tex]
[tex]d = \sqrt{(4 ^ 2 + 0 ^ 2)}[/tex]
[tex]d=\sqrt{16}[/tex]
[tex]d = 4[/tex]
So, the distance is [tex]d = 4[/tex]
Answer:
[tex]d = 4[/tex]
