[tex]\dfrac{(x-2)^2}{49}+\dfrac{(y+5)^2}{36}=1[/tex]
The equation of a elipse:
[tex]\dfrac{x^2}{a^2}+\dfrac{y^2}{b^2}=1[/tex]
The length of the major axis is equal 2a if a > b or 2b if b > a.
We have
[tex]a^2=49\to a=\sqrt{49}=7\\\\b^2=36\to b=\sqrt{36}=6\\\\a > b[/tex]
therefore the length of the major axis is equal 2 · 7 = 14.
