the slope of a perpendicular line = - [tex]\frac{3}{5}[/tex]
the equation of a line in slope-intercept form is
y = mx + c ( m is the slope and c the y-intercept )
rearrange 5x - 3y = 2 into this form
subtract 5x from both sides
- 3y = - 5x + 2 ( divide all terms by - 3 )
y = [tex]\frac{5}{3}[/tex] x - [tex]\frac{2}{3}[/tex]
with slope m = [tex]\frac{5}{3}[/tex]
the slope of a line perpendicular = - [tex]\frac{1}{m}[/tex] = - [tex]\frac{3}{5}[/tex]
