Answer:
0.443 mol/kg.
Explanation:
The formula for molal concentration (b) is
[tex]b = \frac{\text{moles of solute}}{\text{kilograms of solvent}}[/tex]
[tex]\text{Moles of solute} = \text{50.4 g sucrose} \times \frac{ \text{1 mol sucrose}}{\text{342.30 g sucrose} } = \text{0.1472 mol sucrose}[/tex]
[tex]b = \frac{ \text{0.1472 mol}}{ \text{0.332 kg}} = \text{0.443 mol}\cdot\text{kg}^{-1}[/tex]
