Answer:
[tex]\dfrac{42x^2+137x-125}{7x^2+23x-20}[/tex]
Explanation:
You know that the sum of a number and a fraction is ...
... a + b/c = (ac +b)/c
Here, you have ...
... a = 6
... b = -(x+5)
... c = (7x-5)(x+4) = 7x² +23x -20
Then ...
... (ac +b)/c = (6(7x² +23x -20) -(x +5))/(7x² +23x -20)
... = (42x² +138x -120 -x -5)/(7x² +23x -20)
... = (42x² +137x -125)/(7x² +23x -20)
