Answer
B)[tex](x-5)^{2} + y^{2} = 9[/tex]
Step by step explanation
The standard form of circle when center(h, k) and radius r, given is
(x - h)^2 + (y - k)^2 = r^2
Given: (h, k) = (5, 0) and r = 3
Now plug in these values in the standard form, we get
(x - 5)^2 + (y - 0)^2 = 3^2
[tex](x- 5)^{2} + y^{2} = 9[/tex]
Therefore, the answer is B) [tex](x-5)^{2} + y^{2} = 9[/tex]
Thank you :)
