Answer:
B
Step-by-step explanation:
= 6cos ([tex]\frac{5\pi }{6}[/tex]) + 6i sin ([tex]\frac{5\pi }{6}[/tex])
the related acute angle of [tex]\frac{5\pi }{6}[/tex] is [tex]\frac{\pi }{6}[/tex]
= - 6 cos ([tex]\frac{\pi }{6}[/tex]) + 6i sin ([tex]\frac{\pi }{6}[/tex])
= - 6 × [tex]\frac{\sqrt{3} }{2}[/tex] + 6 i × [tex]\frac{1}{2}[/tex]
= - 3[tex]\sqrt{3}[/tex] + 3i → B
