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19-12-2018
Mathematics

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simplify:
[tex] \sqrt[5]{3} + \sqrt{12} + \sqrt{32} [/tex]

Respuesta :

24-12-2018

[tex]\sqrt[5]3+\sqrt{12}+\sqrt{32}=\sqrt[5]3+\sqrt{4\cdot3}+\sqrt{16\cdot2}=\sqrt[5]3+\sqrt4\cdot\sqrt3+\sqrt{16}\cdot\sqrt2\\\\=\boxed{\sqrt[5]3+2\sqrt3+4\sqrt2}[/tex]

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