Answer:
[tex]\dfrac{-x+5}{6x^2-x-12}[/tex]
Step-by-step explanation:
The denominators are the same. You can add the numerators without any extra work.
[tex]=\dfrac{(4x+5)-(5x)}{6x^2-x-12}=\dfrac{-x+5}{6x^2-x-12}[/tex]
The denominator factors as (2x-3)(3x+4), so there are no factors that will cancel with the numerator.
