[tex]\frac{\frac{x}{4}+\frac{1}{8}}{\frac{x^2}{4}}=\frac{\frac{2x}{8}+\frac{1}{8}}{\frac{x^2}{4}}=\frac{\frac{2x+1}{8}}{\frac{x^2}{4}}=\frac{2x+1}{8}:\frac{x^2}{4}=\frac{2x+1}{8}\cdot\frac{4}{x^2}=\frac{2x+1}{2x^2}[/tex]
