Answer:
t1 = 7
t2= 10
t3 = 13
tn+1 = 3n+7
tn+1 -tn =3
Step-by-step explanation:
tn = 3n+4
Let n =1
t1 = 3(1) +4 = 7
Let n =2
t2 = 3(2) +4 = 6+4 = 10
Let n=3
t3 = 3(3)+4 = 9+4 = 13
Let n=n+1
tn+1 = 3(n+1)+4 = 3n+3+7 = 3n+7
Now we need to find t n+1 - tn
tn+1 -tn = 3n+7 - (3n+4)
Distribute the minus sign
= 3n+7-3n-4
3
