mknkepro5ow8kl4 mknkepro5ow8kl4
  • 21-01-2019
  • Physics
contestada

if an object 18mm high is placed 12mm from a diverging lens and the image is formed 4mm in front of the lens what is the height of the image

Respuesta :

carlosego
carlosego carlosego
  • 22-01-2019

To solve this problem we use an amplification formula for divergent lenses

[tex]M = \frac{i}{o} = \frac{h'}{h}[/tex]

Where:

i: distance of the image to the lens

o: Distance from the object to the lens

h = height of the object

h '= height of the image

[tex]M = \frac{4mm}{12mm} = \frac{h'}{18mm}[/tex]

[tex]h'= 18mm\frac{4mm}{12mm}[/tex]

h '= 6 mm

The height is 6 mm

Answer Link

Otras preguntas

What is one reason that Progressives tried to eliminate child labor in the United States?
Help and if you could explain the steps that would be great!
When and where did the Second Continental Congress meet?
Which of the following expressions are equivalent to (-19+3) - 6?
There were 81 runners to start a race. In the first half of the race, 1/3 of them dropped out. In the second half of the race, 2/3 of the remaining runners drop
Why did people in Europe develop this system called feudalism?
someone please help me with this question
find the value of n(33-n=18)please it is urgent​
What is cat fishing bad ? Pls explain with details
Please help me. Thank you if you do.