Here is your answer
B. (12,30)
REASON:
Given,
[tex] y= 2x+6[/tex] .......(i)
[tex] 3x-y= 6 [/tex] .......(ii)
Putting the value of y from eq.i in eq.ii we get
[tex]3x-(2x+6)=6[/tex]
[tex]3x-2x-6=6[/tex]
[tex]=6+6[/tex]
[tex]x=12[/tex]
Putting x=12 in eq.i we get
[tex]y= 2x+6[/tex]
[tex]y= 2×12+6[/tex]
[tex] y= 24+6 [/tex]
[tex] y= 30 [/tex]
So,
[tex]\bold{x=12 and y= 30}[/tex]
Hence answer is (12,30) in which x=12 and y=30
HOPE IT IS USEFUL
