Respuesta :

gmany

Answer:

[tex]\large\boxed{(x-3)^2+(y-7)^2=36}[/tex]

Step-by-step explanation:

The equation of a circle:

[tex](x-h)^2+(y-k)^2=r^2[/tex]

(h, k) - center

r - radius

We have

(3, 7) - center

r = 6 - radius

Substitute:

[tex](x-3)^2+(y-7)^2=6^2\\\\(x-3)^2+(y-7)^2=36[/tex]

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