Answer:
= 15.44 g
Explanation:
The equation for the reaction;
2Al+3 FeSO4 → Al(2)(SO4)(3)+3Fe
We can find;
Moles of iron (ii) sulfate = 42 g/ 151.908 g/mol
= 0.2765 moles
Mole ratio of iron (ii) sulfate : Iron = 3 : 3 = 1 : 1
Therefore;
Moles of Iron produced = 0.2765 moles
Mass of iron = 0.2765 moles × 55.845 g/mol
= 15.44 g
