Answer: Second Option
C(8,8)=1
Step-by-step explanation:
We must calculate a combination
The combination [tex]C (n, r) =\frac{n!}{r!(n-r)!}[/tex]
Where n is the number of elements that you can combine and you choose "r" from them.
So
C (8, 8) is the combination of 8 in 8.
Therefore
[tex]n = 8\\r=8[/tex]
[tex]C(8,8)= \frac{8!}{8!(8-8)!}\\\\C(8,8)=\frac{8!}{8!(0)!}\\\\C(8,8)=\frac{1}{1*1}\\\\C(8,8)=1[/tex]
The answer is the second option
