[tex]
\dfrac{8^{3x}}{2^{10}}=\dfrac{4^{2x}}{16} \\
\dfrac{2^{3(3x)}}{2^{10}}=\dfrac{4^{2x}}{4^2} \\
2^{9x-10}=4^{2x-2} \\
2^{9x-10}=2^{2(2x-2)} \\
2^{9x-10}=2^{4x-4} \\
9x-10=4x-4 \\
5x-6=0 \\
5x=6 \\
\boxed{x=\dfrac{6}{5}}
[/tex]
Hope this helps.
r3t40
