Answer:
[tex]\large\boxed{x>-7\to\{x\ |\ x>-7\}}[/tex]
Step-by-step explanation:
[tex]4x-12<16+8x\qquad\text{add 12 to both sides}\\\\4x-12+12<16+12+8x\\\\4x<28+8x\qquad\text{subtract 8x from both sides}\\\\4x-8x<28+8x-8x\\\\-4x<28\qquad\text{change the signs}\\\\4x>-28\qquad\text{divide both sides by 4}\\\\\dfrac{4x}{4}>-\dfrac{28}{4}\\\\x>-7[/tex]
