Answer:
The smaller diameter is [tex]3.9\ cm[/tex]
Step-by-step explanation:
see the attached figure to better understand the problem
we know that
The diameter of the circle is equal to BD
Applying the Pythagoras Theorem
[tex]BD^{2} =BE^{2} +DE^{2}[/tex]
substitute the given values
[tex]BD^{2} =3^{2} +2.5^{2}\\ BD^{2} =15.25\\ BD=3.9\ cm[/tex]
