Answer:
Domain: x ≥ 3 ⇒ x ∈ [3, ∞)
Step-by-step explanation:
[tex]\text{We know:}\ \sqrt{x}\ \text{exist, if}\ x\geq0.\\\\\text{Therefore in}\ y<\sqrt{2x-6}\ \text{we have the domain:}\\\\2x-6\geq0\qquad\text{add 6 to both sides}\\2x\geq6\qquad\text{divide both sides by 2}\\x\geq3[/tex]
