hrishisup
hrishisup hrishisup
  • 19-08-2019
  • Mathematics
contestada

When the polynomial 3x^3+4x^2+kx+4 is divided by 3x-5 the remainder is 39. Find the value of k and the quotient.

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TaeKwonDoIsDead
TaeKwonDoIsDead TaeKwonDoIsDead
  • 31-08-2019

Answer:

k = 6

Step-by-step explanation:

According to factor/remainder theorem, we will take the value of x which makes 3x-5 equal to 0 and put it into the polynomial and equate it to the remainder.

3x - 5 = 0

3x = 5

x = 5/3

Putting into polynomial:

[tex]3(\frac{5}{3})^3+4(\frac{5}{3})^2+k(\frac{5}{3})+4=39\\3(\frac{125}{27})+4(\frac{25}{9})+\frac{5}{3}k=35\\\frac{125}{9}+\frac{100}{9}+\frac{5}{3}k=35\\\frac{225}{9}+\frac{5}{3}k=35\\\frac{5}{3}k=10\\k=6[/tex]

The value of k is 6

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