Answer:
[tex]\large\boxed{z=\dfrac{1-c}{4+b}}[/tex]
Step-by-step explanation:
[tex]-4z+1=bz+c\qquad\text{subtract 1 from both sides}\\\\-4z=bz+c-1\qquad\text{subtract}\ bz\ \text{from both sides}\\\\-4z-bz=c-1\qquad\text{change the signs}\\\\4z+bz=1-c\qquad\text{distribute}\\\\(4+b)z=1-c\qquad\text{divide both sides by}\ (4+b)\neq0\\\\z=\dfrac{1-c}{4+b}[/tex]
