Answer:
-10x + 8y
Step-by-step explanation:
[tex]\frac{50x^{2} -32y^{2} }{-5x-4y}[/tex]
[tex]\frac{50x^{2} }{-5x} = -10x[/tex]
[tex]\frac{-32y^{2} }{-4y} = 8y[/tex]
