given that
[tex] \frac{h - 8}{j} = k[/tex]
multiply through by j , since it's the L.C.M
thus
[tex]j \times \frac{h - 8}{j} = k \times j[/tex]
cancel out, leaving
[tex]h - 8 = jk[/tex]
making j the subject by dividing through by k
[tex] \frac{h - 8}{k} = \frac{jk}{k} [/tex]
[tex]j = \frac{h - 8}{k} [/tex]
as the final expression for j
