Answer:
Energy of each photon will be [tex]6.468\times 10^{-24}J[/tex]
Step-by-step explanation:
We have given frequency [tex]\nu[/tex] = 98 MHz [tex]=98\times 10^6Hz[/tex]
We have given plank's constant [tex]h=6.6\times 10^{-34}j-s[/tex]
We have to find the energy of each photon
Energy of photon is given by [tex]E=h\nu[/tex], here h is plank's constant and [tex]\nu[/tex] is frequency
So energy [tex]E=6.6\times 10^{-34}\times 98\times 10^6=6.468\times 10^{-24}J[/tex]
