mdtrofort mdtrofort

19-05-2016
Chemistry

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How many grams of NH3 can be produced from 4.54 mol of N2 and excess H2?

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InverseOperator InverseOperator

19-05-2016

First we make a Balanced Chemical Equation:

[tex]N_{2} + 3H_{2} = 2NH_{3} [/tex]

Now we can solve using the Mole Ratio:

4.54 mol N2 × 2 / 1 × 17.04 g/mol NH3
= 154.72 g

If you need further clarification, feel free to comment.

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