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Two teams of nine members each engage in a tug of war. Each of the first team’s members has an average mass of 65 kg and exerts an average force of 1354 N horizontally, on the ground. Each of the second team’s members has an average mass of 71 kg and exerts an average force of 1364 N horizontally, on the ground. What is the magnitude of the acceleration of the two teams?

Respuesta :

Answer:

.team 1 a = 20.8 m/s²   team 2  a = 19.2 m/s²

Explanation:

Let's use Newton's second law to calculate the acceleration of the two groups

   

      F = ma

      a = F / M

Group 1

      a = 9 1354/9 65

      a = 20.8 m / s²

Group 2

     a = 9 1364/9 71

     a = 19.2 m / s²

If the two groups pull against each other, group 1 should win, by creating a greater acceleration.

     Δa = 20.8 -19.2

     Δa = 1.6 m / s²