Answer:
167,3 grams of O2 (g)
Explanation:
According to the following balanced equation:
C3H8 + 5 02 ---> 3 CO2 + 4 H20
We calculate the mass of the moles:
5 mol O2 = 16grams/mol x2x 5= 160 grams/mol
1 mol C3H8= 3 x12 grams/mol + 8 x 1 gram/mol= 44 grams/mol
If 44 grams C3H8 react with--------- 160 grams O2
46 gramsC3H8 react with --------X = (46x160)/44 =167, 3 grams O2
