Answer:
The 16th term in the expression is 39
Step-by-step explanation:
we have
[tex]a(n)=-6+3(n-1)[/tex]
we know that
To find out the 16th term, substitute the value of n=16 in the expression above
so
For n=16
substitute
[tex]a(16)=-6+3(16-1)[/tex]
[tex]a(16)=-6+3(15)[/tex]
[tex]a(16)=-6+45[/tex]
[tex]a(16)=39[/tex]
therefore
The 16th term in the expression is 39
