Answer:
a. 1, -2
Step-by-step explanation:
[tex]f(x)=\frac{3}{x^{2}+x-2}\\f(x)=\frac{3}{(x+2)(x-1)}\\[/tex]
Find when the denominator equates to 0.
x+2 = 0
x = -2
x-1 = 0
x = 1
Set restrictions for x in the denominator to find the vertical asymptotes
x ≠ -2, 1
