Answer:
3x-2y-2=0
3x-2y+10=0
Step-by-step explanation:
let the slope of the line be 'm'
and also [tex](x1,y1)=(0,5)[/tex]
[tex](x2,y2)=(2,8)[/tex]
we know the formula for finding slope [tex]m=\frac{Y2-Y1}{X2-X1}[/tex]
[tex]m=\frac{8-5}{2-0} \\m=\frac{3}{2}[/tex]
The equation of the line will be as,
[tex](y-y1)=m(x-x1)\\(y-5)=\frac{3}{2}(x-0)\\ y-10=3x\\ 23x-2y+10=0\\(y-2)=\frac{3}{2}(x-2)\\ 2y-4=3x-6\\3x-2y-2=0[/tex]
