Answer:
1±√5
Step-by-step explanation:
[tex]\bf x^2-2x-2=0\Rightarrow x=\displaystyle\frac{-(-2)\pm\sqrt{(-2)^2-4*2*(-2)}}{2}\Rightarrow\\\\\Rightarrow x=\displaystyle\frac{2\pm\sqrt{4+16}}{2}=\displaystyle\frac{2\pm\sqrt{20}}{2}=\displaystyle\frac{2\pm2\sqrt{5}}{2}\Rightarrow\\\\\Rightarrow \boxed{x=1\pm\sqrt{5}}[/tex]
