JonathanElPro6804 JonathanElPro6804
  • 20-12-2019
  • Chemistry
contestada

For a given reaction, ΔH = -19.9 kJ/mol and ΔS = -55.5 J/Kmol.

The reaction will have ΔG = 0 at __________ K.

Assume that ΔH and ΔS do not vary with temperature.

Respuesta :

dsdrajlin
dsdrajlin dsdrajlin
  • 21-12-2019

Answer:

359 K

Explanation:

The Gibbs free energy can be calculated using the following expression.

ΔG = ΔH - T.ΔS

where,

ΔG is the Gibbs free energy

ΔH is the enthalpy of the reaction

T is the absolute temperature

ΔS is the entropy of the reaction.

When ΔG = 0,

ΔH - T.ΔS = 0

ΔH = T.ΔS

T = ΔH/ΔS = (-19.9 × 10³ J/mol) / (-55.5 J/K.mol) = 359 K

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