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The balanced chemical reaction will be:

C3H8 + 5O2 = 3CO2 +4H2O

We are given the amount of propane gas to be burned. This will be our starting point.

38.95 g C3H8 ( 1 mol C3H8 / 44.1 g C3H8 ) ( 5 mol O2/1 mol C3H8)(32 g O2 / 1 mol O2) =141.32 g O2

Therefore, the reaction consumes approximately 142 grams of oxygen gas.

The correct answer is 0.8830 moles of propane

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