Answer:
ΔV=2.481 L
Explanation:
As we know that
[tex]\frac{PV}{T}=\frac{P_{2}V_{2} }{T_{2}}[/tex]
Always use temperature in Kelvin and Pressure in Atm
Given Data
P₁=1.03 atm
P₂=225 torr =(225/760)=0.296 atm
V₁=1.30
T=17⁰C=290.15 K
T₂=-31⁰C=242.15 K
Substitute the given values
So
[tex]\frac{1.03*1.30}{290} =\frac{V_{2}(0.296) }{242.15} \\1.2224*10^{-3}V_{2}=4.6217*10^{-3}\\ V_{2}=3.781[/tex]
You have to find the difference of two volumes:
So
ΔV=3.781 - 1.30
ΔV=2.481 L
