Answer:
= +∞ if x→ +∞
= -∞ if x→ −∞
Step-by-step explanation:
[tex]\lim_{x \to +\infty}\frac{9x^{2} }{x+2} = \lim_{x \to +\infty}\frac{9x^{2} }{x}= \lim_{x \to +\infty}9x = +\infty\\\\ \lim_{x \to -\infty}\frac{9x^{2} }{x+2} = \lim_{x \to -\infty}\frac{9x^{2} }{x}= \lim_{x \to -\infty}9x = -\infty\\[/tex]
