Answer:
140 J
Explanation:
From the the question, the mass of the man =70.0 kg and the speed at which the man is walking =2.0 m/s.
[tex]K.E = \frac{1}{2}m {v}^{2} [/tex]
where K.E = the kinetic energy, m=mass and v= speed.
By substitution,
[tex]K.E = \frac{1}{2} \times 70 \times {2}^{2} [/tex]
[tex] \implies \: K.E = \frac{280}{2} [/tex]
[tex] \implies K.E =140[/tex]
Hence the kinetic energy of the man is 140J
