Answer:
31.2K
Explanation:
The following data were obtained from the question:
n = 1.42 mol
V = 3L
P = 123 kPa = 123000Pa
Recall: 101325Pa = 1atm
123000Pa = 123000/101325 = 1.21atm
R = 0.082atm.L/Kmol
T =?
Using the ideal gas equation PV = nRT, we can obtain the temperature as follows:
PV = nRT
T = PV/nR
T = (1.21 x 3)/(1.42 x 0.082)
T = 31.2K
