Answer:
x=3,-8
Step-by-step explanation:
[tex]x^2+5x=24\\add ~both~sides~(\frac{5}{2})^2\\x^2+5x+(\frac{5}{2})^2=24+\frac {25}{4}\\(x+\frac{5}{2})^2=\frac{96+25}{4}\\(x+\frac{5}{2})^2=\frac{121}{4}\\x+\frac{5}{2}=\pm \frac{11}{2}\\x=-\frac{5}{2} \pm \frac{11}{2} \\either~x=-\frac{5}{2} +\frac{11}{2} =\frac{6}{2} =3\\or~x=-\frac{5}{2} -\frac{11}{2} =-\frac{16}{2} =-8[/tex]
