Answer:
The two boats are 323.72 m apart.
Step-by-step explanation:
See the attached diagram.
B is the point of observation and AB is the height of the parasailer i.e. 75 m.
Now, from the right triangle Δ ABC,
[tex]\tan 79^{\circ} = \frac{AB}{AC} = \frac{75}{AC}[/tex]
⇒ AC = 14.58 meters.
Again, from the right triangle Δ ABD,
[tex]\tan 12.5^{\circ} = \frac{AB}{AD} = \frac{75}{AD}[/tex]
⇒ AD = 338.30 meters.
Hence, CD = AD - AC = 338.30 - 14.58 = 323.72 m
Therefore, the two boats are 323.72 m apart. (Answer)
