Answer:
The volume is 17, 3 L
Explanation:
We use the formula PV=nRT. The conditions STP are 1 atm of pressure and 273 K of temperature. We convert grams into moles of CO2. We calculate the weight of 1 mol of CO2.
Weight 1 mol C02 = weight C+ (weight 0)x2= 12g + 16g x2= 44 g/mol
44 g ---1 mol
34g---x=(34g x 1 mol)/44g= 0,77 mol
PV=nRT V=(nRT)/P
V= (0,77mol x 0,082 latm/K mol x 273K)/ 1 atm= 17, 3 liters
