Answer:
225
Step-by-step explanation:
Using the basic components of summation ∑
∑n = [tex]\frac{1}{2}[/tex] n(n + 1) and ∑1 = n
Thus
∑ (2n - 1) ← for n = 1 to 15
= ∑2n - ∑1
= 2∑n - ∑1
= 2 ([tex]\frac{1}{2}[/tex] n(n + 1)) - n
= n(n + 1) - n ← Evaluate for n = 15 ( the upper value )
= 15 × 16 - 15
= 240 - 15
= 225
