Remainder theorem again...
[tex]p(x)=x^3+x^2-4x-4[/tex]
[tex]p(-1)=(-1)^3+(-1)^2-4(-1)-4=0[/tex]
So Yes, [tex]x+1[/tex] is a factor.
Answer:
Yes
Step-by-step explanation:
If x + 1 is a factor, x = -1 has to be a root
(-1)³ + (-1)² - 4(-1) - 4
0
