Answer:
∠ BCD = 28°
Step-by-step explanation:
The centre angle BOD is twice the angle on the circumference ∠ BFD, thus
∠ BOD = 2 × 76° = 152°
The sum of the interior angles of quadrilateral BODC = 360°
The angles at the point of contact of the tangents and the radii are 90°
Sum the interior angles and equate to 360
∠ BCD + 90 + 152 + 90 = 360
∠ BCD + 332 = 360 ( subtract 332 from both sides )
∠ BCD = 28°
