[tex] {x}^{2} + 12x + 6 = 0 \\ D = {12}^{2} - 4 \times 6 = 144 - 24 = 120 = \\ = (2 \sqrt{30} )^{2} \\ x_1= \frac{ - 12 + 2 \sqrt{30} }{2} = - 6 + \sqrt{30} \\ x_2= \frac{ - 12 - 2 \sqrt{30} }{2} = - 6 - \sqrt{30} [/tex]
But i don't see correct answer here
Ox= 6 + V30
Ox= 6+ V30
Ox= 60 V6
Ox= 6 + V6
or maybe i don't understend something
